CVE-2022-50706:详情

CVE-2022-50706

0.05%V4
2025-12-24
10h55 +00:00
2026-05-23
15h24 +00:00
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CVE 描述

net/ieee802154: don't warn zero-sized raw_sendmsg()

In the Linux kernel, the following vulnerability has been resolved: net/ieee802154: don't warn zero-sized raw_sendmsg() syzbot is hitting skb_assert_len() warning at __dev_queue_xmit() [1], for PF_IEEE802154 socket's zero-sized raw_sendmsg() request is hitting __dev_queue_xmit() with skb->len == 0. Since PF_IEEE802154 socket's zero-sized raw_sendmsg() request was able to return 0, don't call __dev_queue_xmit() if packet length is 0. ---------- #include #include int main(int argc, char *argv[]) { struct sockaddr_in addr = { .sin_family = AF_INET, .sin_addr.s_addr = htonl(INADDR_LOOPBACK) }; struct iovec iov = { }; struct msghdr hdr = { .msg_name = &addr, .msg_namelen = sizeof(addr), .msg_iov = &iov, .msg_iovlen = 1 }; sendmsg(socket(PF_IEEE802154, SOCK_RAW, 0), &hdr, 0); return 0; } ---------- Note that this might be a sign that commit fd1894224407c484 ("bpf: Don't redirect packets with invalid pkt_len") should be reverted, for skb->len == 0 was acceptable for at least PF_IEEE802154 socket.

CVE 信息

EPSS

EPSS 是一种预测漏洞被利用可能性的评分模型。

EPSS 评分

EPSS 模型生成一个介于 0 到 1(即 0% 到 100%)之间的概率评分。评分越高,漏洞被利用的可能性越大。

EPSS 百分位

百分位用于根据 EPSS 评分对 CVE 进行排名。例如,EPSS 百分位为第 95 的 CVE,其被利用的可能性高于 95% 的其他 CVE。因此,百分位可用于比较不同 CVE 的 EPSS 评分。

参考资料