CVE-2023-54293:详情

CVE-2023-54293

0.03%V4
2025-12-30
12h23 +00:00
2025-12-30
12h23 +00:00
指定 CVE 通知
随时了解指定 CVE 的变更。
管理通知

CVE 描述

bcache: fixup btree_cache_wait list damage

In the Linux kernel, the following vulnerability has been resolved: bcache: fixup btree_cache_wait list damage We get a kernel crash about "list_add corruption. next->prev should be prev (ffff9c801bc01210), but was ffff9c77b688237c. (next=ffffae586d8afe68)." crash> struct list_head 0xffff9c801bc01210 struct list_head { next = 0xffffae586d8afe68, prev = 0xffffae586d8afe68 } crash> struct list_head 0xffff9c77b688237c struct list_head { next = 0x0, prev = 0x0 } crash> struct list_head 0xffffae586d8afe68 struct list_head struct: invalid kernel virtual address: ffffae586d8afe68 type: "gdb_readmem_callback" Cannot access memory at address 0xffffae586d8afe68 [230469.019492] Call Trace: [230469.032041] prepare_to_wait+0x8a/0xb0 [230469.044363] ? bch_btree_keys_free+0x6c/0xc0 [escache] [230469.056533] mca_cannibalize_lock+0x72/0x90 [escache] [230469.068788] mca_alloc+0x2ae/0x450 [escache] [230469.080790] bch_btree_node_get+0x136/0x2d0 [escache] [230469.092681] bch_btree_check_thread+0x1e1/0x260 [escache] [230469.104382] ? finish_wait+0x80/0x80 [230469.115884] ? bch_btree_check_recurse+0x1a0/0x1a0 [escache] [230469.127259] kthread+0x112/0x130 [230469.138448] ? kthread_flush_work_fn+0x10/0x10 [230469.149477] ret_from_fork+0x35/0x40 bch_btree_check_thread() and bch_dirty_init_thread() may call mca_cannibalize() to cannibalize other cached btree nodes. Only one thread can do it at a time, so the op of other threads will be added to the btree_cache_wait list. We must call finish_wait() to remove op from btree_cache_wait before free it's memory address. Otherwise, the list will be damaged. Also should call bch_cannibalize_unlock() to release the btree_cache_alloc_lock and wake_up other waiters.

CVE 信息

EPSS

EPSS 是一种预测漏洞被利用可能性的评分模型。

EPSS 评分

EPSS 模型生成一个介于 0 到 1(即 0% 到 100%)之间的概率评分。评分越高,漏洞被利用的可能性越大。

EPSS 百分位

百分位用于根据 EPSS 评分对 CVE 进行排名。例如,EPSS 百分位为第 95 的 CVE,其被利用的可能性高于 95% 的其他 CVE。因此,百分位可用于比较不同 CVE 的 EPSS 评分。

参考资料